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Navigationhard#283

If GS outbound is 400 kt, GS homebound is 500 kt, and total distance is 1800 NM, the PET is at:

A

800 NM from departure

B

900 NM from departure

C

1000 NM from departure

Correct
D

1100 NM from departure

Explanation

PET = D × GS(home) / (GS(out) + GS(home)) = 1800 × 500 / (400 + 500) = 900,000 / 900 = 1000 NM from departure.

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