FAA figures/8080-2H/Figure 38

Figure 38: Airplane landing distance table

FAA-CT-8080-2H · Sport, Recreational, Private & Remote Pilot supplement · asked on the Private Pilot test

FAA Figure 38Airplane landing distance tableFAA-CT-8080-2H · Sport, Recreational, Private & Remote Pilot supplement
How to read it: Read the row for the pressure altitude and temperature, then apply the notes: subtract 10 % per 4 knots of headwind, add 10 % per 60 °F above standard, and 20 % more for a dry grass runway.

2 FAA questions that refer to this figure

  1. Question 1 · Private Pilot

    (Refer to FAA-CT-8080-2H, Figure 38.) Determine the approximate landing ground roll distance. Pressure altitude: 5,000 ft Headwind: Calm Temperature: 101°F

    • A.445 feet.
    • B.545 feet.
    • C.495 feet.
    Show answer and explanation

    Correct: B. 545 feet.

    The 5,000-foot column of Figure 38 is based on 41 degrees F, which is the standard temperature at that altitude, and shows a 495-foot ground roll. Note 2 adds 10% for each 60 degrees F above standard. The given 101 degrees F is 60 degrees F above standard, so 495 x 1.10 = 544.5, about 545 feet. The calm wind means no headwind reduction. 445 feet is the sea-level value, and 495 feet leaves out the temperature correction.

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  2. Question 2 · Private Pilot

    (Refer to FAA-CT-8080-2H, Figure 38.) Determine the total distance required to land over a 50-foot obstacle. Pressure altitude: 5,000 ft Headwind: 8 kts Temperature: 41°F Runway: Hard surface

    • A.837 feet.
    • B.956 feet.
    • C.1,076 feet.
    Show answer and explanation

    Correct: B. 956 feet.

    At 5,000 feet and 41 degrees F (standard, so no temperature correction), Figure 38 gives 1,195 feet total to clear a 50-foot obstacle on a hard surface. Note 1 decreases the distance 10% for each 4 knots of headwind, so an 8-knot headwind is a 20% reduction: 1,195 x 0.80 = 956 feet. 1,076 feet corresponds to only a 10% reduction, and 837 feet to a 30% reduction.

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